TSTP Solution File: SEV408^5 by Duper---1.0
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% File : Duper---1.0
% Problem : SEV408^5 : TPTP v8.1.2. Released v4.0.0.
% Transfm : none
% Format : tptp:raw
% Command : duper %s
% Computer : n015.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Thu Aug 31 19:24:55 EDT 2023
% Result : Theorem 5.75s 5.95s
% Output : Proof 5.75s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.11 % Problem : SEV408^5 : TPTP v8.1.2. Released v4.0.0.
% 0.00/0.12 % Command : duper %s
% 0.12/0.33 % Computer : n015.cluster.edu
% 0.12/0.33 % Model : x86_64 x86_64
% 0.12/0.33 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33 % Memory : 8042.1875MB
% 0.12/0.33 % OS : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33 % CPULimit : 300
% 0.12/0.33 % WCLimit : 300
% 0.12/0.33 % DateTime : Thu Aug 24 04:11:35 EDT 2023
% 0.12/0.33 % CPUTime :
% 5.75/5.95 SZS status Theorem for theBenchmark.p
% 5.75/5.95 SZS output start Proof for theBenchmark.p
% 5.75/5.95 Clause #0 (by assumption #[]): Eq (Not (Exists fun G => ∀ (A : Iota → Prop), G A → Exists fun B => And (cF B) (∀ (Xx : Iota), A Xx → B Xx))) True
% 5.75/5.95 Clause #1 (by clausification #[0]): Eq (Exists fun G => ∀ (A : Iota → Prop), G A → Exists fun B => And (cF B) (∀ (Xx : Iota), A Xx → B Xx)) False
% 5.75/5.95 Clause #2 (by clausification #[1]): ∀ (a : (Iota → Prop) → Prop),
% 5.75/5.95 Eq (∀ (A : Iota → Prop), a A → Exists fun B => And (cF B) (∀ (Xx : Iota), A Xx → B Xx)) False
% 5.75/5.95 Clause #3 (by clausification #[2]): ∀ (a : (Iota → Prop) → Prop) (a_1 : Iota → Prop),
% 5.75/5.95 Eq (Not (a (skS.0 0 a a_1) → Exists fun B => And (cF B) (∀ (Xx : Iota), skS.0 0 a a_1 Xx → B Xx))) True
% 5.75/5.95 Clause #4 (by clausification #[3]): ∀ (a : (Iota → Prop) → Prop) (a_1 : Iota → Prop),
% 5.75/5.95 Eq (a (skS.0 0 a a_1) → Exists fun B => And (cF B) (∀ (Xx : Iota), skS.0 0 a a_1 Xx → B Xx)) False
% 5.75/5.95 Clause #5 (by clausification #[4]): ∀ (a : (Iota → Prop) → Prop) (a_1 : Iota → Prop), Eq (a (skS.0 0 a a_1)) True
% 5.75/5.95 Clause #10 (by fluidSup #[5, 5]): ∀ (a : Prop), Eq ((fun _ => a) True) True
% 5.75/5.95 Clause #17 (by betaEtaReduce #[10]): ∀ (a : Prop), Eq a True
% 5.75/5.95 Clause #18 (by falseElim #[17]): False
% 5.75/5.95 SZS output end Proof for theBenchmark.p
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